If @foo exists, Perl takes a good guess about [bar] , and is almost always right.
—
http://perldoc.perl.org/perldata.html#Scalar-value-constructors
Why I avoid Perl?
If @foo exists, Perl takes a good guess about [bar] , and is almost always right.
—
http://perldoc.perl.org/perldata.html#Scalar-value-constructors
Why I avoid Perl?